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        <title>Solar Photovoltaic</title>
        <link>https://forum.csers.ly/</link>
        <pubDate>Mon, 21 Sep 2026 07:50:49 +0000</pubDate>
        <language>en</language>
            <description>Solar Photovoltaic</description>
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        <title>MENA 2019 Solar Outlook Report</title>
        <link>https://forum.csers.ly/discussion/9/mena-2019-solar-outlook-report</link>
        <pubDate>Tue, 19 Feb 2019 09:52:31 +0000</pubDate>
        <category>Solar Photovoltaic</category>
        <dc:creator>sbelhaj</dc:creator>
        <guid isPermaLink="false">9@/discussions</guid>
        <description><![CDATA[<p>A reporter at the World Future Energy Summit (WFES) 2019 wrote
“MENA Solar Market Reaches Inflection Point”.&nbsp;
The MENA pipeline needle is rapidly moving in the direction of real
investments and project execution. In fact, there are more than 12 GW of solar
projects that have either been awarded, are under construction or in operation
in the region, according to the “2019 Solar Outlook Report”, issued recently by
the Middle East Solar Industry Association (MESIA)</p>

<p>Within six years, the sunny Middle East will have as much
solar power as the US has today, and more than Germany. &nbsp;By 2030, it will be approaching China’s
current level. After a slow start, this oil and gas-dominated region has woken
up to the potential of the sun</p>

<p>Like other solar markets coming of age, the MENA region has
seen a significant shift in attitude by the utilities and power companies,
which have gone from seeing solar as an expensive gimmick to a resilient
renewable energy juggernaut that can economically compete with more traditional
sources of energy—and provide a sustainable decarbonization alternative to the
oil and gas status quo.</p>

<p>The report predicts unprecedented growth in solar projects
and related industries in the next 10 years in neighbouring countries.&nbsp; More importantly, it is no longer just a hype
but a reality that’s already started in many of the MENA countries.&nbsp; The report gives highlights of MENA’s leading
solar markets, covering 11 countries that include Algeria, Bahrain, Egypt, Jordan,
Kuwait, Morocco, Oman, Pakistan, Saudi Arabia, Tunisia, and UAE.&nbsp; Sadly, Libya is missing on the radar for now
and the near foreseeable future, unless by some miracle the country pulls
itself together and starts building for the future instead of deepening the hole
its already in.</p>

<p>In the forefront, the Renewable Energy Authority of Libya (REAOL)
bears the responsibility and burden of shaping Libya’s future in energy supply,
which could turn it into the next National Energy Corporation of Libya (NECOL).</p>

You can download a copy of the full report from <a rel="nofollow" href="http://www.mesia.com/wp-content/uploads/2019/01/MESIA-Solar-Outlook-Report-Single-2019.pdf" title="Link: http://www.mesia.com/wp-content/uploads/2019/01/MESIA-Solar-Outlook-Report-Single-2019.pdf">http://www.mesia.com/wp-content/uploads/2019/01/MESIA-Solar-Outlook-Report-Single-2019.pdf</a>.<br />]]>
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    <item>
        <title>Will solar energy replace fossil fuels in Libya?</title>
        <link>https://forum.csers.ly/discussion/8/will-solar-energy-replace-fossil-fuels-in-libya</link>
        <pubDate>Mon, 28 Jan 2019 22:34:23 +0000</pubDate>
        <category>Solar Photovoltaic</category>
        <dc:creator>AdelDiyaf</dc:creator>
        <guid isPermaLink="false">8@/discussions</guid>
        <description><![CDATA[<div><br /></div><div>&nbsp;With the increased energy demands in the near future, Libya will be forced to burn more oil and gas.Recently, the country has been struggling to satisfy its escalating energy demands. Although the fule and electricity is very cheap (nearly free), over the past few years the Power Grid in Libya has suffered difficult conditions, which resulted in severe materialistic damage to power generation units, transmission networks. All of that has placed the electrical power grid in a difficult and critical situation leading to a large deficit in meeting the demand for electricity use, and thus resorting to power cuts for long periods of time. On the other hand, The solar energy in Libya can be measured by the solar radiation rate of 7.5 kW per day in the promising areas, which receives between 3000 and 3,500 hours of sunshine each year. &nbsp;According to researchers,Libya could generate approximately five times the amount of energy from solar power than it currently produces in crude oil. So depends on that, do you think that solar energy will replace fossil fuels in Libya? , and what &nbsp;do we need to make that true?</div><div><br /></div>]]>
        </description>
    </item>
    <item>
        <title>LambertW function overflow problem</title>
        <link>https://forum.csers.ly/discussion/7/lambertw-function-overflow-problem</link>
        <pubDate>Fri, 25 Jan 2019 23:07:39 +0000</pubDate>
        <category>Solar Photovoltaic</category>
        <dc:creator>sbelhaj</dc:creator>
        <guid isPermaLink="false">7@/discussions</guid>
        <description><![CDATA[<p><i>Welcome to ‘Solar in Libya’ forum and I hope you find this
first post of the forum of interest to you.</i></p><b>

</b><p>Recently, I was working on an implementation of ‘single
diode model’ to evaluate the performance of solar cells/modules under real
operating conditions and as part of the solution to the model I got introduced
to the LambertW function (also known as the Omega function).</p><p><img alt="" src="https://forum.csers.ly/uploads/editor/bi/ktqaw8dy5hl5.jpg" /><br /></p><p>Everything went fine
initially until I started to change the operating conditions and discovered
that my single diode model was going out of bound under certain conditions.<br /></p><p><img alt="" src="https://forum.csers.ly/uploads/editor/bk/hjm4r94v4o4u.jpg" /><br /></p><p>After some
investigation, I discovered that the term passed to the LambertW function was
becoming too large and causing an overflow, even when evaluated as double
precision.&nbsp; In fact, it was raising (e) to
powers greater than ~710 which was the real problem.&nbsp; The result from the LambertW function would
still be relatively small if only I could get past the overflow error
of the input term.&nbsp; This lead me to
think that perhaps I could scale down the input term in a way that will allow
me later to scale up the LambertW function result without introducing
errors.&nbsp; Looking closely at the inners of
the LambertW function, it became obvious that the problem was not so simple.&nbsp; So what is the LambertW function?, you may
ask.<br /></p><p><img alt="" src="https://forum.csers.ly/uploads/editor/1f/qlx1twqdj8zl.jpg" /><br /></p><p>You can find a good explanation of the LambertW function in
the following link: "<a rel="nofollow" href="https://blogs.mathworks.com/cleve/2013/09/02/the-lambert-w-function/">Cleve Moler on Mathematics and Computing</a>".</p><p>There is a fast
solution developed by&nbsp;Toshio Fukushima&nbsp;“Precise and fast computation of Lambert W-functions
without transcendental function evaluations, Journal of Computational and
Applied Mathematics 244 (2013) 77–89”.&nbsp; It
relies on lookup tables to avoid slow transcendental functions (evaluating
expensive exponentials) but has a limitation on the range of values it can
cover (typically -65&lt;x&lt;65).<br /></p><h2>Solving the overflow error problem:</h2><p>Given the LambertW function form y = w.e^w, it stands to
reason that log(y) = log(w) + w.&nbsp; This
should solve the overflow problem since the problem only occurs when
we raise (e) to the power of w &gt; ~710.&nbsp;
All that is needed now is to solve the logarithmic form of the equation
to determine the value of w for a given input value log(y).</p>

<p>First, since y in our ‘single diode model’ is of the form
y=A.e^B, log(y) is simply log(A) + <b></b><b></b>B. &nbsp;Hence we avoid the overflow problem
altogether. Next, we turn our attention to developing a logarithmic LambertW
(LambertWLog) function solution.</p>

<p>The solution involves using one of the Monte Carlo methods
to perform iterative root-finding using derivatives,
such as Newton-Raphson, Halley or Schröder iterations.</p><p>Using Halley’s
iteration with an initial guess for w is:</p><p>w’ = w – f(w) / (f’(w)
– f(w).f”(w) / [2f’(w)])</p><p>Applying some substitution
and simplification, where:</p><p>&nbsp; &nbsp; &nbsp;log(y) = log(w) + w<br />&nbsp; &nbsp; &nbsp;0 = log(w) + w – log(y),&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
where:&nbsp; log(y) = log(A) + B, a
constant<br />&nbsp; &nbsp; &nbsp;f(w) = log(w) + w – log(y)<br />&nbsp; &nbsp; &nbsp;f’(w) = (1+w)/w&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
1st derivative<br />&nbsp; &nbsp; &nbsp;f”(w) = -1/(w.w)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 2nd derivative<br /></p><p>Results in:</p><p>&nbsp; &nbsp; &nbsp;w’ = w – fn / (1/w + 1 + fn / [2w(w + 1)])&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;where:&nbsp; fn
= log(w) + w – log(y),&nbsp; log(y) = log(A) + B</p><p>Given a good initial approximation, a solution can be reached
within 2 or 3 iterations.&nbsp; As it turns out, log(y) is a very good initial approximation of w and works equally well.&nbsp; The LambertWLog function can resolve very large w values &gt; 1,000,000 when the regular LambertW would crash and burn at ~710.</p><h2><b></b></h2>]]>
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